Question

For the following reaction, 6.98 grams of silver nitrate are mixed with excess sodium chloride. The reaction yields 5.48 grams of silver chloride.


NaCl (aq) + AgNO3 (aq) = AgCl (s) + NaNO3 (aq)





(1) What is the theoretical yield of silver chloride ?

grams



(2) What is the percent yield for this reaction ?

%

Answer 1

the actual yield is 5.48

Answer 2

okay attempt a solution showing me all the work

Answer 3

yes 5.48 correct

Answer 4

okay now what is the theoritical yield

Answer 5

I get trouble on this part

Answer 6

dont guess look at the equation what is infront of NaCl 1 or 2

Answer 7

can you show me step by step with me

Answer 8

1

Answer 9

oh yes we ve started

Answer 10

good you saw 1 so that is it

Answer 11

what of Ag N03

Answer 12

1

Answer 13

excellent

Answer 14

you ve been given 6.98 grams of AgNO3 from the question right

Answer 15

yes

Answer 16

the trick is to find the theoritical value of AgCl you must find the moles of AgNO3

Answer 17

do you know how to find the moles of AgNO3

Answer 18

do IOOK AT THE PERIDIC TABLE

Answer 19

108 IS THE ATOMIC NUMBER FOR Ag (silver)

Answer 20

to find the moles of AgNO3 you need the molar mass and you can get them from the periodic table

MM OF N=14

MM OF O = 16

MM OF AG=197

NB :YOU ARE NOT LOOKING FOR ATOMIC NUMBER

Answer 21

ok

Answer 22

NOW YOU NEED TO FIND THE MOLAR MASS OF AGNO3

MM OF AGNO3=197+14+16(3)=
NB:SINCE THERE ARE 3 OXYGEN IN THE FORMULA YOU MULTIPLY 16 BY 3

Answer 23

GIVE ME THE VALUE PLEASE

Answer 24

259

Answer 25

wonderful

now find the MOLES of AGNO3

MOLES = MASS/MOLAR MASS

CAN YOU PLEASE FIT IN THE VALUES AND GIVE ME YOUR EQUATION

Answer 26

6.98/259

Answer 27

.0269

Answer 28

WONDERFUL THAT IS THE MOLES OF AGNO3

Answer 29

sorry the website shut down yesterday
we ll continue some other time