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Find the limit; lim x->2 from the left (3)/(x-2)
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nope, not sure how that will apply to this problem.
I am looking at other similar example and I think the answer to this might be -infinity but how?
\[\lim_{x\rightarrow 2^-}\frac{3}{x-2}\] If we approach from the left, this implies\[x<2\]Hence \[x-2<0\]Thus we can conclude \[\frac{1}{x-2}<0\] Therefore,\[\lim_{x\rightarrow 2^-}\frac{3}{x-2}\rightarrow -\infty\]
for these type of limits, the graph can also help x=2 is a vertical asymptote |dw:1363681790029:dw| From graph you can see that as you approach "x=2" from left the curve goes toward neg infinity
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