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Mathematics 13 Online
OpenStudy (anonymous):

find df/dy of f(x,y) =x^y. anyone helps me, please

OpenStudy (anonymous):

Take log...it will help u

OpenStudy (anonymous):

f = x^y log f = y log x 1/f df/dy = y * 1/x dx/dy + log x

OpenStudy (anonymous):

it's partial derivative, still apply?

OpenStudy (anonymous):

can I do dy/dx =1/dx/dy =1/y(x)^(y-1)?

OpenStudy (anonymous):

\[f(x,y)=f=x^y\\ {\partial f\over\partial y}=?\\ \ln f=y\ln x\\ {1\over f}{\partial f\over\partial y}=\ln x\\ \implies{\partial f\over\partial y}=x^y\ln x \]

OpenStudy (anonymous):

another hint.. x is const with respect to 'y' so, it is d/dx(a^x)

OpenStudy (anonymous):

@Hoa cheers :)

OpenStudy (anonymous):

I got it. so, my argue is wrong, right?

OpenStudy (anonymous):

sadly yes..

OpenStudy (anonymous):

LOL, thanks... crazy thinking me!!!

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