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find df/dy of f(x,y) =x^y. anyone helps me, please
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Take log...it will help u
f = x^y log f = y log x 1/f df/dy = y * 1/x dx/dy + log x
it's partial derivative, still apply?
can I do dy/dx =1/dx/dy =1/y(x)^(y-1)?
\[f(x,y)=f=x^y\\ {\partial f\over\partial y}=?\\ \ln f=y\ln x\\ {1\over f}{\partial f\over\partial y}=\ln x\\ \implies{\partial f\over\partial y}=x^y\ln x \]
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another hint.. x is const with respect to 'y' so, it is d/dx(a^x)
@Hoa cheers :)
I got it. so, my argue is wrong, right?
sadly yes..
LOL, thanks... crazy thinking me!!!
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