Question

How do I solve this logarithm?

Answer 1

\[\log _{7}(x+1) + \log _{7}(x-5) = 1\]

Answer 2

have you tried this ?
basically, first step would be to use the property
\(\large\log_ax+\log_ay=\log_axy\)

Answer 3

so that would give me\[\log _{7}(x+1)(x-5)\]or\[\log _{7}(x ^{2}-4x-5)\]right?

Answer 4

absolutely correct!
thats your left side.
now by the definition of logarithm, you can use :
\(\large if, \log_ab=c, \implies b=a^c\)

Answer 5

so, what can you say about \(\log _{7}(x ^{2}-4x-5)=1\)

Answer 6

I'm not sure how to do that... am I supposed to solve for x at any point?

Answer 7

what up what your face man