Find all real numbers x such that \[4x + 2 \ge 14\] and \[-21x + 1 > 22\] I am not looking for someone to give me the answer here, I am looking for someone to check my work to make sure I'm doing it right as I want to catch any mistakes now before I submit the assignment for grading. Posting the answers here will not get a medal!
\[4x + 2 \ge 14\] is equal to \[x \ge 4\]
-21x + 1 > 22 -1 -1 -21x > 21 /-21 /-21 x < -1
How do you get x greater than or equal to 4?
What u have done for the second part is right:) Pls chck the first part
There's a mistake in second part too
oops sorry my bad/. yup u r @Abdul_shabeer
basically when I redid my work for the first part I got... \[x \ge 3\]
That's right
Okay and looking at the work for the 2nd one, I'm not really sure where I went wrong.
Everything is fine except the final line
21 / -21 = -1 correct?
Okay, so when I was taught this, I was told that if your graphing these equations on a number line and you have to divide by a negative, the inequality sign flips to the opposite sign. Is that wrong?
@abdul_shabeer If your graphing these equations on a number line and you have to divide by a negative, the inequality sign flips to the opposite sign. Is that wrong?
If x is less than -1, then it doesn't satisfy the inequality
So there would be no real numbers in this set?
Wait, nevermind. We can still add the numbers from \[x \ge 3\] So it would be an open dot on 3 with the shading to the right?
@ajprincess did I do it right?
Well I thnk u r right. cos real numbers include all positive negative integers , decimal numbers and all
\(x\ge3\) the dot also will be a shaded one
I mean ur second part too is right
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