Question

Sam is throwing a baseball straight up in the air. He releases the ball 5ft. from the ground at a velocity of 95 ft./s. The acceleration due to gravity is 32 ft./s^2.

This problem can be solved using the following equation.
(1/2) 32t^2 - 95t-5=0

How many seconds will it take the ball to reach the ground (round to the nearest hundredth)

A.5.99 Seconds
B. 6.49 seconds
C.7.04 seconds
D.5.54 seconds

Answer 1

Do you think you could help me @ash2326

Answer 2

It's similar to the last question
\[\frac 1 2 32t^2-95t-5=0\]
or
\[16t^2-95t-5=0\]
\[a=16, b=-95, c=-5\]
Now you need to try this @kaek98
Use quadratic formula

Answer 3

Ok I just tried it on a piece of paper and I got 5.989 if that was rounded it would be 5.99

Answer 4

Good :)

Answer 5

can you help me on this little question?

State wether the following is true: sometimes, never, or always

19+ |x| >18

Answer 6

A. never
B. sometimes
C. always
D. cannot be determined from the given information

Answer 7

Subtract 19 from both the sides

Answer 8

so the 19 in the beginning is gone

Answer 9

where does the other 19 subtract from? the 18?

Answer 10

yes you'd get
\[|x|>18-19\]
While you simplify this, think about absolute value function |x|, about its basic property.

Answer 11

so it would be |x|> -1

Answer 12

yes, now tell me is this true always, sometimes or never

Answer 13

true?

Answer 14

always

Answer 15

true always*?

Answer 16

yes, how do you say that?

Answer 17

What do you mean?

Answer 18

What's the reason ?

Answer 19

Because x is greater than -1

Answer 20

It's not given in the question!

Answer 21

what?

Answer 22

that x is greater than 1
hint: it's something to do with the absolute value function

Answer 23

I still don't quite get it. I mean the only thing I can think of is that 19 is greater than 18 to begin with

Answer 24

Absolute value is always greater than or equal to 0
\[|x| \ge 0\]
for any value of x so
\[|x| \ge -1\]
this would be true always the left side will be a positive no.

Answer 25

Ohh Okay

Answer 26

Do you understand ?

Answer 27

Yes

Answer 28

Thank you

Answer 29

Welcome :)