Write the equation of the line that passes through (2, 4) and (1, –3) in slope-intercept form.

y = 7x – 10

y = 7x + 10

y = 7x + 18

y = 7x – 18

Question

Write the equation of the line that passes through (2, 4) and (1, –3) in slope-intercept form.

 y = 7x – 10

 y = 7x + 10

 y = 7x + 18

 y = 7x – 18

anonymous · Answer

plug in one point to y=7x+b.
so 4=7(2)+b

anonymous · Answer

y=7x+ your answer from plugging in

anonymous · Answer

The equation of the gradient of this line is $$m=\frac{ y _{1}-y_{2} }{ x_{1}-x_{2} }$$ So your two points (2,4) (1,-3) can be used to find the gradient, we see that it is $$m=\frac{ 4--3 }{ 2-1 }$$ which gives m=7. Now the equation of a straight line is given by $$y-y_{1}=m(x-x_{1})$$ which you can use either of your two coordinates, they will both give the same answer. Using (2,4) as it is easier gives us. $$y-4=7(x-2)$$$$y-4=7x-14$$$$y=7x-10$$ Which is your final answer :)