Question

d/dx int_{1}^{sinx} sqrt{2+t^{4}}dt

Answer 1

Use the chain rule. In this case the inner function is \(\sin x\)

Answer 2

\[d/dx \int\limits_{1}^{sinx}\sqrt{2+t^{4}}dt\]

Answer 3

sooo\[\sqrt{3}-\sqrt{2+\sin^{4}x}*cosx\]

Answer 4

correct?

Answer 5

What is with the \(\sqrt{3}\)?

Answer 6

by F.T.C part II differentiate F(1)-F(sinx) correct?
if so d/dx of F(1) = sqrt{2+{1^4}} = sqrt(3)?

Answer 7

d/dx of F(1) = 0 because F(1) is constant.

Answer 8

\(F(1)\) is a constant with respect to \(x\).

Answer 9

that was my thoughts! thanks!