Question

Display the data in the chart attached below by making a box and whisker plot.
Explain how you made it.

Answer 1

@rajathsbhat

Answer 2

statistics....we meet again.

Answer 3

LOL. Are you not so good with them?

Answer 4

not so good is an overstatement.

Answer 5

*understatement. I suck at it.

Answer 6

Oh, ok. thats fine, no worries. Ill go beg someone else.
:D

Answer 7

Thanks for looking,tho.

Answer 8

http://www.purplemath.com/modules/boxwhisk3.htm

Answer 9

see if this helps :)

Answer 10

Hmm... could you explain it step by step?

Answer 11

hold on

Answer 12

ok. ty:)

Answer 13

you find the median of your data.

Answer 14

have u done that

Answer 15

one second - let me do it.

Answer 16

Median: 68

Answer 17

goodTo divide the data into quarters, you then find the medians of these two halves. Note: If you have an even number of values, so the first median was the average of the two middle values, then you include the middle values in your sub-median computations. If you have an odd number of values, so the first median was an actual data point, then you do not include that value in your sub-median computations. That is, to find the sub-medians, you're only looking at the values that haven't yet been used

Answer 18

hmmm.

Answer 19

let me read all that.

Answer 20

srry

Answer 21

why are you sorry?

Answer 22

too much to read :)

Answer 23

indeed. lol.

Answer 24

could u simplify it?

Answer 25

divide the data into quarters, you then find the medians of these two halves.

Answer 26

hmmm...could u show me the steps by using the DRAW button?

Answer 27

Please.

Answer 28

im not sure http://www.purplemath.com/modules/boxwhisk.htm

Answer 29

Hmm. Okay. Thanks.

Answer 30

Lets see.....

Answer 31

@eigenschmeigen

Answer 32

@jim_thompson5910

Answer 33

what's your question?

Answer 34

I have to make a box and whisker plot for the data shown at http://assets.openstudy.com/updates/attachments/5148e6dee4b05e69bfab6578-help123please.-1363732200597-screenshot20130319at5.28.53pm.png

Answer 35

I also would like to know how to make box and whisker plots by myself.

Answer 36

Find the median first

Then split the data into two groups (the median is the cut off point) and find the median of each group. The first quartile is the median of the lower half, the third quartile is the median of the upper half

Answer 37

the median is 68.

Answer 38

ok.....hmmm...

Answer 39

oohhhh divide it into 2?

Answer 40

8/2=4

Answer 41

so 4 sets of data in the lower quartile and 4 in the upper?

Answer 42

yes the median is 68

Answer 43

Okay.

Answer 44

show me step by step how to make it using the DRAW button please?

Answer 45

so the sorted number set

61, 64, 65, 68, 68, 70, 71, 73

turns into

61, 64, 65, 68 | 68, 70, 71, 73

when you split the data in half along the median

Answer 46

Uh-huh, I see.

Answer 47

the median of 61, 64, 65, 68 is 64.5, so Q1 = 64.5

Answer 48

Okay.

Answer 49

what's Q3?

Answer 50

Let me see. One second.

Answer 51

ok

Answer 52

70.5

Answer 53

good

Answer 54

what's your IQR

Answer 55

i don't know how to get that...

Answer 56

IQR = Q3 - Q1

Answer 57

it's basically the distance from each endpoint of the box

Answer 58

Oh,ok.

Answer 59

70.5-64.5?

Answer 60

yep

Answer 61

thats 6.

Answer 62

now find the min and max

Answer 63

The min and max?

Answer 64

yes, the smallest and largest data values

Answer 65

oh... U mean
min = 61
max = 73

Answer 66

good, now determine if the min is an outlier or not

Answer 67

you do this by seeing if the min is above

median - 1.5*IQR

Answer 68

Why 1.5?

Answer 69

just a number that some statistician a long time ago determined was the best number to see if outliers exist on a box and whisker plot

Answer 70

I think it was Tukey

Answer 71

Oh.

Answer 72

I'm not sure how or why he got 1.5, but it works

Answer 73

and people agree on it

Answer 74

and the iqr is?

Answer 75

you just found it

Answer 76

o sorry....6

Answer 77

yep

Answer 78

1.5 x 6 = 9

Answer 79

subtract that from the median 68

Answer 80

Hmm. Ok. WOW, lots of steps
:/
LOL.

Answer 81

it's not so bad once you get used to them

Answer 82

56.

Answer 83

no

Answer 84

68 - 9 is not 56

Answer 85

it's 59

Answer 86

o right sorry.

Answer 87

so that's your lowest threshold

Answer 88

i punched the wrong numbers into the calculator.

Answer 89

basically that's the smallest the min can be

Answer 90

sorry bout that.

Answer 91

any smaller than 59, and the min is an outlier

Answer 92

Ah,ok.

Answer 93

so we do NOT have an outlier for the min because the min (which is 61) is greater than the threshold of 59

Answer 94

now compute

median + 1.5*IQR

Answer 95

Mhmm. Okay. One second - will log off for like 2 mins,k?

Answer 96

ill brb