The graph below represents which system of inequalities? A) y

Question

The graph below represents which system of inequalities?

A)  y < -2x + 6
     y < x + 2
B)  y <= -2x + 6
     y <= x + 2
C)  y < 2/3x - 2
     y > 2x + 2
D)  None of the above

anonymous · Answer

attachment

anonymous · Answer

@Mertsj

aripotta · Answer

which choice can we automatically eliminating

aripotta · Answer

eliminate*

anonymous · Answer

I don't know. that is the problem.

aripotta · Answer

we can automatically eliminate b because the lines in the graph are dashed, not solid. and <= would be a solid line

aripotta · Answer

now you can graph a and c and see which choice is the answer

anonymous · Answer

So it is either A or C?

aripotta · Answer

or d

anonymous · Answer

I think it is D.

aripotta · Answer

have you tried graphing though

anonymous · Answer

on paper, yeah. I think that is it.

anonymous · Answer

@SingleSixxs_Fiance

aripotta · Answer

i just graphed a and this is what it looks like. a is your answer

anonymous · Answer

Okay thank you!

aripotta · Answer

how did you graph it

anonymous · Answer

not like that. can you show me how you did that?

aripotta · Answer

y < -2x + 6

start by plotting the y-intercept which in this case is 6. so make a point at (0,6)

then use the slope which is -2. slope is rise/run, so from (0,6), go down 2 and over to the right 1

aripotta · Answer

then make a point there and make a dashed line

anonymous · Answer

ohhhhh okay! is that all?

aripotta · Answer

and you would shade under the line

aripotta · Answer

yea, then just do it to the other line and you should get it

aripotta · Answer

attachment

anonymous · Answer

Okay, so now for this one: The graph below represents which system of inequalities? y <= -2x + 3 y <= x + 3 y >= -2x + 3 y >= x + 3 y <= -3x + 2 y <= -x + 2 y > -2x + 3 y > x + 3

aripotta · Answer

attachment

anonymous · Answer

attachment

aripotta · Answer

oh. do you think you can try that one yourself?

anonymous · Answer

I did. none of my graphs matched that one.

aripotta · Answer

can i see your graphs

anonymous · Answer

yes, but can you tell me how to do the x axis part? Imma go over my graphs and check.

aripotta · Answer

what do you mean?

anonymous · Answer

how do i plot and stuff on my graph for the x axis. i think i did it wrong.

aripotta · Answer

you plot the y-intercept first. then use the slope to plot the next point

anonymous · Answer

which is?

aripotta · Answer

here i'll use this as an example

y <= -2x + 3

the y-intercept is 3. so the first point you need to plot is (0,3).

the slope is -2. slope is rise/run. so from the point (0,3), go down 2 and over to the right 1, which would be (1,1). plot a point there.

since the inequality is <=, our line is solid. so make a solid line through your two points. shade under the line.

anonymous · Answer

|dw:1363736756403:dw|