Question

I did this question and got p=1 and -2 but i want a second opinion. Please show all working.

The function f(x)=x^3 - p^2x^2 + 2x - p has remainder -5 when it is divided by x + 1. Find the possible values of the constant p.

Answer 1

Given that The function f(x)=x^3 - p^2x^2 + 2x - p has remainder -5 when it is divided by x + 1.

So we have f(-1) = -5
now plugging -1 in place of x in f(x) we get the quadratic plotynomial in p that is
\[-1-p ^{2}-2-p=-5\]
simplifying we get \[p ^{2}+p-2=0\]
that gives us p = 1 and -2
Keep It up Crimson!!

Answer 2

thx :)

Answer 3

Its My pleasure!

Answer 4

yeah thts wat i got