Suppose that stoichiometric amounts of nitrogen gas and hydrogen gas react in a calorimeter to produce 5.00 g of ammonia gas. The calorimeter temperature rises 0.42°C. The calorimeter and water have a combined heat capacity of 32.16 kJ/K. Calculate the heat of formation of ammonia, ΔH°f, in kJ/mol. The formation reaction for ammonia is: 0.5N2(g) + 1.5H2(g) → NH3(g).
q=mC(delta)T
then scale that to 1 mole
What is the work to that.? I know what to do, but I cannot figure it out. Thanks
you don't need to find the work, only the enthalpy of formation
I need the heat formation though. So what would I put?
q=mC(delta)T
you're finding q
I found q, but how do I scale to one mole?
how many moles of ammonia is 5 grams of ammonia
actually just divide the molar mass of ammonia by 5 grams, then multiply q by that number
Okay, I think I got it. Thank you very much.
no problem
That did not match any of my multiple choice answers. I got 19.883. The closest was 13.
i got 58.0109922
The answer choices are. -46, -13.5, -3.97, 3.97, and 13.5
since the temperature rises, meaning that reaction is releasing heat, so it's exothermic so we're only looking at the negative values
-46 sounds right
Did you work it out?
no i'm not sure why it didn't work out, but i actually know that to be the right value, i'm trying it out hold on
ok thanks a lot
this guy solved it here: http://openstudy.com/study#/updates/510bf8f9e4b0d9aa3c470cb6
You helped a lot. Appreciate it!
no problem, sorry for the confusion
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