Question

solve this trig equation by factoring

Answer 1

\[\sqrt{2} tanx cosx -tanx=0\]

Answer 2

factor out tan x

Answer 3

then?

Answer 4

\[\tan x(\sqrt{2}\cos x-1)=0\]

Answer 5

Set each factor equal to 0 and solve

Answer 6

oh ok thank you very much!
Can you help me with another one?

Answer 7

I can try

Answer 8

\[sinx \tan ^{2} x =sinx\]

Answer 9

subtract sin x from both sides and then factor out sin x

Answer 10

\[\sin x \tan ^2x-\sin x=0\]

Answer 11

\[\sin x(\tan ^2x-1)=0\]

Answer 12

oh ok that one was easy. What about \[2\sin ^{2} x + 3\sin x +1=0\]

Answer 13

\[(2\sin x+1)(\sin x+1)=0\]

Answer 14

ok thank you very much!!!!

Answer 15

yw

Answer 16

@Mertsj
\[3sint=2\cos ^{2} t\]

Answer 17

cos^2t = 1-sin^2t

Answer 18

can you tell me step by step?

Answer 19

\[3\sin t=2(1-\sin ^2t)\]

Answer 20

\[3\sin t=2-2\sin ^2t\]

Answer 21

\[2\sin ^2t+3\sin t-2=0\]

Answer 22

\[(2\sin t-1)(\sin t+2)=0\]

Answer 23

@Mertsj
for sint+2 it equal sint=-2 and thats not on the unit circle

Answer 24

That's right. There is no solution from that factor because sin t is always between -1 and 1 so all solutions come from the first factor.

Answer 25

@Mertsj oh ok. and for solving cosx=.75 How do you do it using a graphing calculator?

Answer 26

inverse cos (.75) enter

Answer 27

ok thank you very much

Answer 28

yw