A poll shows that 76% of voters in a city favor an initiative to increase spending on public schools. If 10 voters are selected at random, what is the probability that exactly five of them will vote in favor of the initiative?
@jim_thompson5910 ,
this is a binomial distribution problem
5.1% 10% 27% 15%
in this case, n = 10, p = 0.76 and k = 5
Do u have any idea of binomail probability distribution ?
so @jim_thompson5910 is 5% my answer?
P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k) P(X = 5) = (10 C 5)*(0.76)^(5)*(1-0.76)^(10-5) P(X = 5) = (10 C 5)*(0.76)^(5)*(0.24)^(10-5) P(X = 5) = (252)*(0.76)^(5)*(0.24)^5 P(X = 5) = (252)*(0.253553)*(0.000796) P(X = 5) = 0.050877 So it's closest to 5.1% after rounding
Thank you @jim_thompson5910
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