Question

A recent poll found that 45% of eligible voters are planning to vote in favor of a new by-law. Suppose you randomly survey six voters. What is the probability that at least three of the voters plan to vote in favor of the new by-law?

Answer 1

@jim_thompson5910

Answer 2

wow this is going to be a pain

Answer 3

Haha i said the same thing.

Answer 4

because "at least 3" means
3 or
4 or
5 or
6

and you have to compute each of those and add. or else you can compute
0 or
1 or
2 and subtract that from 1

Answer 5

so you can to either compute four numbers and add them up
or three numbers, add them up and then subtract the result from 1

which do you choose?

Answer 6

A recent poll found that 45% of eligible voters are planning to vote in favor of a new by-law. Suppose you randomly survey six voters. What is the probability that at least three of the voters plan to vote in favor of the new by-law? P(X ≥ 3) = sum of Binomial terms from x = 3 to x = 6: 6Cx (0.45)^x (1-0.45)^(6-x)= 0.055855.8% so my answer is 55.8%

Answer 7

ok

Answer 8

\[\binom{6}{3}(.45^3)(.55^3)+\binom{6}{4}(.45^4)(.55^2)+\binom{6}{5}(.45^5)(.55)+.45^6\]

Answer 9

yeah that is what i get too

Answer 10

awww ya got it wrong the answer is 13.2%

Answer 11

The answer is 55.8%