If g(x) = 6 + x + 2e^x, find g^-1(8)

Question

If g(x) = 6 + x + 2e^x,  find g^-1(8)

anonymous · Answer

put the term 1/(6+x+ whatever)  then replace x by 8

anonymous · Answer

but you have to find the inverse of the equation before plugging x into it.

tkhunny · Answer

Thsi would be a VERY INTERESTING exploration if the answer x = 0 were not obvious.

anonymous · Answer

my bad wait....my brain is doing multiple tasks

anonymous · Answer

x = 0 haha

anonymous · Answer

my bad that was an easy question. I forgot about the rule used with the natural log

anonymous · Answer

try zero

anonymous · Answer

oh, what @tkhunny  said
if it was not obvious, you could not do it

anonymous · Answer

here's the inverse 
-(2e^(x-6))+x-6

tkhunny · Answer

@Best_Mathematician When a closed-form inverse is not possible, please don't attempt to tell us that you have found one.

anonymous · Answer

well i am not in condition to find it....so i told wolframalpha to do it...its his answer...blame him lol

tkhunny · Answer

No, that is not correct.  You did not understand the answer you received.  That "W" is VERY, VERY important.  You just ignored it.