Question

For the following reaction, 4.51 grams of iron are mixed with excess oxygen gas. The reaction yields 5.73 grams of iron(III) oxide.


4 Fe (s) + 3 O2 (g) = 2 Fe2O3 (s)





(1) What is the theoretical yield of iron(III) oxide ?

grams



(2) What is the percent yield for this reaction ?

%

Answer 1

4 Fe (s) + 3 O2 (g) ----->2 Fe2O3 (s)

56 *4 grams of Fe react with 3 * 32 grams of O2 to give (4*56 + 6*16) of Fe2O3

Answer 2

So the theoretical yield of iron(III) oxide = 320g = (4*56 + 6*16)

Answer 3

u mean Wrong answer ?

Answer 4

can you tell me what is the molecular weight of CH2Cl2

Answer 5

u only have mentioned the answer what you need

Answer 6

For the following reaction, 4.77 grams of iron are mixed with excess oxygen gas. The reaction yields 5.71 grams of iron(III) oxide.


4 Fe (s) + 3 O2 (g) =2 Fe2O3 (s)





(1) What is the theoretical yield of iron(III) oxide ?

grams



(2) What is the percent yield for this reaction ?

Answer 7

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Answer 8

jsu show me the step

Answer 9

how to do this and plus the answer so I get the hang on how to do this