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Solve for b 2*log(b)/log(a)+4*log(a)/log(b) = 9 where a>b>1
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Actually \[2\log_{a}b+4\log_{b}a = 9\]
use, \(\large\log_xy=\dfrac{1}{\log_yx}\) then put \(\log_ba=x\) you'll get a quadratic in 'x', which you can solve easily.
see if you get \(4x^2-9x+2=0\)
is "a" a constant..or we have to find some numerical value of "a" also..otherwise the ans will be in terms of "a"
^yes, the ans will be in terms of "a"
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that means we dont have to find the value of "a"..can we find some numerical value of "a" by any means??
2 unknows and only 1 equation. i don't think it'll be possible to find numerical value of a or b
yeah,i also think so..
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