Question

if z = 2(cos π/9 + i sin π/9) then what is z^3? please help !!

Answer 1

apply de moivres theorem....

Answer 2

thank you

Answer 3

i dont think its correct

Answer 4

why wht happened?

Answer 5

are you able to solve it??

Answer 6

DeMoivre's formula gives the following:

(r*(cos(theta) + i*sin(theta))^n =

(r^n) * (cos(n*theta) + i*sin(n*theta)).

Answer 7

z³ = 2³ * (cos [3* (π/9)] + i sin [3* (π/9)]

@Lindie Simplify the expression on the right.

What did you get?

Answer 8

@Lindie Question?