Solve square root of x plus 1 end root plus 5 equals x

Question

anonymous · Answer

Could you express it in terms of numbers?

anonymous · Answer

$$\sqrt{x+1} + 5=x$$

anonymous · Answer

Try substracting by five, then taking x-5 to the power of 2, to get rid of the radical.

anonymous · Answer

Subtracting*

comm.dan · Answer

No solution because you can't have a plus and minus square root for an imperfect square. @JessieJakeway

anonymous · Answer

Thank you! @Comm.Dan You're the best! :)

comm.dan · Answer

No problem!! Any more questions?? @JessieJakeway

anonymous · Answer

Simplify the square root of 128 end root plus 2 square root of 112 end root minus 2 square root of 98 end root minus 6 square root of 28

comm.dan · Answer

Could u please put it into terms of numbers?

anonymous · Answer

$$\sqrt{128}+2\sqrt{112}-2\sqrt{98}-6\sqrt{28}$$

comm.dan · Answer

Thx

jim_thompson5910 · Answer

x = 8 is a solution to $$\Large \sqrt{x+1} + 5=x$$ since plugging in x = 8 gives you a true equation


$$\Large \sqrt{x+1} + 5=x$$

$$\Large \sqrt{8+1} + 5=8$$

$$\Large \sqrt{9} + 5=8$$

$$\Large 3 + 5=8$$

$$\Large 8=8$$

which is true, so that verifies that x = 8 is a solution

comm.dan · Answer

Where did u get the 8 from? @jim_thompson5910

comm.dan · Answer

|dw:1363841778973:dw| @JessieJakeway