Question

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Answer 1

try to simplify the above equation to the form x^2+y^2=r^2
r is the radius of the circle
then put those given points in the equation and see which one satisfies .that is the required centre.

Answer 2

Ok cool. Thanks! Ill let you know what i find.

Answer 3

oops little mistake

Answer 4

the equation is (x-h)^2+(y-k)^2=r^2
(h,K) is the centre..the above equation i have written is for circle with origin as centre

Answer 5

So if i were to plug in A: center (–1, 1); radius 4 it would look like (-1 - (-1))^2 + (1 - 1)^2 = 4^2?

Answer 6

no..It is (-1-1)^2+rest is right..

Answer 7

then if right hand side is equal to left hand side , that is the answer otherwise do the same for another one

Answer 8

But x and h are the same (-1) so if the equation is (x-h)^2+(y-k)^2=r^2 wouldnt it be (-1 - (-1))^2?

Answer 9

im sorry again..here (x,y) are the points on the circumference of the circle.It is very easy.just compare the given equation to (x-h)^2+(y-k)^2=r^2..(h,K) is the centre and r is the radius

Answer 10

you Got the answer??

Answer 11

Not yet. Im still trying to figure it out...