Question

f(x) = x^2 – 3x + 1, find all the values of c on the interval (0, 1) that satisfy the Mean Value Theorem.

Answer 1

@rizwan_uet can u help?

Answer 2

do you know mean value theorem???

Answer 3

tea

Answer 4

. [f(b) - (a)]/(b - a)

Answer 5

yea*

Answer 6

now evaluate this

Answer 7

okay i'm having trouble plugging in

Answer 8

here a = 0 and b = 1
can you do it now???

Answer 9

okay

Answer 10

so its f(1) - (0)/ 1 - 0

Answer 11

find f(1) and f(0) by simply putting 1 and 0 in f(x) = x^2 – 3x + 1

Answer 12

okay

Answer 13

so f(x) = 1^2 - 3(1) + 1 ?

Answer 14

yap

Answer 15

okay its -1

Answer 16

now find f(0)

Answer 17

okay its 1

Answer 18

so the values are -1, and 1?

Answer 19

now what will this result in???
f(1) - (0)/ 1 - 0

Answer 20

its 0

Answer 21

no

Answer 22

no?