Rewrite the given equation in slope-intercept form: 15x - 3y = 12
Determine the slope and the y-intercept for the linear equation: y = 6x
Slope intercept form \[y=mx+c\] m=slope of the line c= y-intercept we have \[15x-3y=12\] Add 3y to both the sides, what would you get?
i have no idea? :(
\[15x-3y=12\] Add 3y to both the sides \[15x-3y+3y=12+3y\] \[15x-\cancel {3y}+\cancel{3y}=12+3y\] \[15x=12+3y\] Do you get this?
y = 5x+4?
close, \[15x-12=3y\] Divide both sides by 3
So that is right. y = 5x+4
oh 5x-4
yes
let me try this one... Choose the slope and y-intercept of the equation: y = - 7x + 4
yes :)
um help...
\[y=mx+c\] m= slope c= y intercept
-7 (0,4)
Correct :D
Yea!! Determine the slope and the y-intercept for the linear equation: y = 6x
I'll rewrite it for you \[y=6x+0\] Try now
The slope is 6 and the y-intercept is (0, 0)
yes ;D
Good!
Determine the slope of a line perpendicular to a line whose slope is - 3.
@smartrob If you have more questions, close this and ask a new. I'll answer this product of two perpendicular lines' slopes is -1 \[m1\times m2=-1\] here you have one line's slope
ok
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