Ask your own question, for FREE!
Chemistry 18 Online
OpenStudy (anonymous):

Can anybody explain how to balance equations? Can you like dumb it down. Not because I'm stupid, but because I don't understand chemistry. :(

OpenStudy (carniel):

If you post an equation I can explain it while helping you with it :)

OpenStudy (anonymous):

okay:) let me go find one

OpenStudy (anonymous):

CH3CH2OH + O2 yields CO2 + H2O where it says yields is where the arrow is supposed to be.

OpenStudy (carniel):

Ok this is simple :) Well 1st off you need to know that both sides have to be equal

OpenStudy (carniel):

Since ___CH3CH2OH + ___O2 > __CO2 + ___H2O

OpenStudy (carniel):

If you put numbers in front were the lines are they multiply with all of the elements in that one equation. Example: If I put a 2 in front of H2O it would = H4O2

OpenStudy (anonymous):

how would it be H4O2?

OpenStudy (anonymous):

because you are multiplying the number 2 to the whole H2O. The number you are multiplying (the coefficient) will be multiplied by every number in the equation so it would be : 2*H2=H4 and 2*O=O2

OpenStudy (anonymous):

okay. I get that now but im still confused about the rest of it ....

OpenStudy (anonymous):

ok, so like Carniel said, you are trying to get the same amount of stuff on both sides.

OpenStudy (anonymous):

so it would be CH3CH2OH + 3 O2 = 2 CO2 + 3 H2O

OpenStudy (anonymous):

it is somewhat difficult for me to explain through chat, however, I can suggest you use this video to learn. Im sorry http://www.youtube.com/watch?v=UGf60kq_ZDI or http://www.youtube.com/watch?v=ZzwziP04448

OpenStudy (anonymous):

its okay:) I appreciate the help!

OpenStudy (anonymous):

no problem! and sorry I could't explain it to you

OpenStudy (anonymous):

its okay:)

OpenStudy (carniel):

Sorry I couldn't help more :( Had a meeting to go to

OpenStudy (anonymous):

its okay @Carniel :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!