Ask
your own question, for FREE!
Mathematics
12 Online
Find the linear approximation to f(x) at x = x o. Graph the function and its linear approximation. f(x) = sqrt(x), x o = 1
Still Need Help?
Join the QuestionCove community and study together with friends!
@zepdrix can u help?
linear approx is: \[y=f'(c)(x-c)+f(c)\]
i tried but i got stuck is this correct so far? L(x) = f(1) + f'(1) (x - 1) = 0 + 1/2sqrt(x) ( x - 1)
f(1) = 1, not 0 f'(1) = 1/2
therefore: the linear approximation if say: sqrt(1.2) is\[y=1+\frac12(1.2-1)=1.1\]
Still Need Help?
Join the QuestionCove community and study together with friends!
umm so i made a mistake on the 0 right?
yep, and also on the f'(1) f'(1) not equal 1/2sqrt(x)
ohh okay
f'(1) = 1/2sqrt(1) = 1/2
so its 1 + 0 ( x - 1) ?
Still Need Help?
Join the QuestionCove community and study together with friends!
??? is it correct?
no, 0 does not equal 1/2
\[y=f(1)+f'(1)(x-1)\] \[y=1+\frac12(x-1)\]
ohh ok
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
17 hours ago
0 Replies
0 Medals
4 days ago
3 Replies
2 Medals
1 week ago
3 Replies
0 Medals
2 days ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal