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Find the linear approximation to f(x) at x = x o. Graph the function and its linear approximation. f(x) = sqrt(x), x o = 1
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@zepdrix can u help?
linear approx is: \[y=f'(c)(x-c)+f(c)\]
i tried but i got stuck is this correct so far? L(x) = f(1) + f'(1) (x - 1) = 0 + 1/2sqrt(x) ( x - 1)
f(1) = 1, not 0 f'(1) = 1/2
therefore: the linear approximation if say: sqrt(1.2) is\[y=1+\frac12(1.2-1)=1.1\]
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umm so i made a mistake on the 0 right?
yep, and also on the f'(1) f'(1) not equal 1/2sqrt(x)
ohh okay
f'(1) = 1/2sqrt(1) = 1/2
so its 1 + 0 ( x - 1) ?
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??? is it correct?
no, 0 does not equal 1/2
\[y=f(1)+f'(1)(x-1)\] \[y=1+\frac12(x-1)\]
ohh ok
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