Solve the following system of equations. 2x + y = 3 x = 2y - 1 @hartnn
Just plug in the second expression into the x value of the first expression so you will get \[2(2y-1) + y = 3\] then solve for y, plug in that value into either equation and solve for x.
Hint 2x + y = 3 2(2y-1) + y = 3 ... plug in x = 2y - 1 4y - 2 + y = 3 5y - 2 = 3 I'll let you finish up
y=1
now use that to find x
x=1
you got it
For the following system, use the second equation to make a substitution for y in the first equation. 2x + y = 6 y = 3x + 4 What is the resulting equation? y+ 2x+y= 6 2x+y+ 3x+ 4 = 6 2x+ (3x+ 4) = 6
which one do you think it is? use the last problem as a guide
x=-3
y=16
but what is the answer to the initial question
For the following system, use the second equation to make a substitution for y in the first equation. 3x + y = 1 y + 4 = 5x What is the resulting equation?
you need to solve for y in the second equation first
Based on the lesson, which of the following would be the best approach for solving this system by substitution? 5x = y + 6 2x - 3y = 4 Solve the first equation forx. Solve the first equation fory. Solve the second equation forx. Solve the second equation fory.
which one do you think it is
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