Question

How to factor by grouping?
2c^2 + 4cd + 3c + 3d
This is what I have so far:
Split the equation in two:
2c^2 + 4cd and 3c + 3d
gcf: 2c gcf: 3

Distribute backwards:
2c(? + ?)2c^2 + 4cd and 3(? + ?)3c + 3d
1c + 2d 1c + d

Now I'm stuck because I'm not sure that I've done it right

Answer 1

2c^2 + 4cd + 3c + 3d

(2c^2 + 4cd) + (3c + 3d )

2c(c + 2d) + (3c + 3d )

2c(c + 2d) + 3(c + d )

this is as far as you can go since (c+2d) and (c+d) aren't the same

Answer 2

so maybe there's a typo somewhere

Answer 3

The question was:
Determine whether the following polynomials can be factored by grouping. If so, factor the polynomials showing all work. If not, explain why this method will not work.

I just figured that you could and that I was doing something wrong. I over checked it and that's the right equation, so do you think it can't be grouped?

Answer 4

So it can't be grouped if that's the correct equation (and whoever wrote this didn't make a typo)

So it cannot be factored this way.

Answer 5

One basic reason why is notice how the coefficients of the first group are 2 and 4. So the second coefficient is 2 times bigger than the first

Answer 6

the second group has coefficients of 3 and 3

they are the same and they are NOT in the same proportion as the first two coefficients

so that's why it doesn't work

Answer 7

Oh okay, thank you for explaining!

Answer 8

yw

Answer 9

btw, thx for posting your work/steps showing what you got on it

Answer 10

Oh no problem. I always thought it was easier to understand if someone knew what I was doing wrong.

Answer 11

yes that helped me see your thoughts on it and not many students would post their work (if they even did the work at all lol)