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limit-->0 sin(x^2)/3x^2
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Separate the limit into the top and bottom, meaning focus on one part then the other.
Notice the bottom portion, 3x^2, will go to 0. This can be determined by a direction substitution to get 3(0)^2 = 0
The top, sin(x^2), can be determined the same way. Using direction subtitution, sin(0^2) = sin(0) = 0. thus, the limit converges to 0
substitution* Notice, I broke it up into 2 parts. If you wish, you can directly substitute zero. Usually, that should be your go-to-solution. However, you have to learn to recognize when a direct substitution will work, and where it will not work.
I hope this helps!
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