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Mathematics 9 Online
OpenStudy (anonymous):

Use the integral test to determine whether the series below converges or diverges.

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty}\frac{ n }{ n^2+9 }\]

OpenStudy (anonymous):

That means that you just compute the integral, with the same bounds. Can you setup this integral?

OpenStudy (anonymous):

i will be quite, but you sure as heck don't need no integral test for this use the eyeball test

OpenStudy (anonymous):

well the book wants me to use the integral test but not sure how to do it

OpenStudy (anonymous):

replace the sum by an integral, using the bounds 1 and infinity

OpenStudy (anonymous):

and replace the \(n\) by an \(x\)

OpenStudy (anonymous):

the integral diverges so that means what?

OpenStudy (anonymous):

so does the sum

OpenStudy (anonymous):

but you knew that already, because the degree of the denominator is only one more than the degree of the numerator

OpenStudy (anonymous):

I know how to set up the integral

OpenStudy (anonymous):

i think it will be from 0 to infinty

OpenStudy (anonymous):

because the degree differs by only 1, it will not converge

OpenStudy (anonymous):

oh yeah that's true, so whats the point of using the integral test?

OpenStudy (anonymous):

@mido really makes no difference, what happens at the beginning is irrelevant

OpenStudy (anonymous):

@Ldaniel not everything is a rational function the integral test is useful when it is less obvious

OpenStudy (anonymous):

try

OpenStudy (anonymous):

i mean when the convergence or divergence is less obvious

OpenStudy (anonymous):

What does the integral test yield? .. infinity?

OpenStudy (anonymous):

in this case yes, because the sum diverges

OpenStudy (anonymous):

are u set up it

OpenStudy (anonymous):

so the series diverge ?

OpenStudy (anonymous):

i think this

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