Question

A certain capacitor in a circuit has a capacitive reactance of 36.8 Ω when the frequency is 136 Hz. What capacitive reactance does the capacitor have at a frequency of 20.3 kHz?

Answer 1

I keep coming up with the wrong answer

I use
Xc = 1/(2*pi*F*C)
rearrange and solve for C:
C = 1/(2*pi*F*Xc)
F = frequency
Xc = capacitave reactance

Then

Xc = 1/(2*pi*F*C)
solve for Xc using C found above and same frequency

Answer 2

didnt convert my 20.3 to kHz. solved.

Answer 3

The reactance of the capacitor is inversely proportional to frequency.
Reactance at 1 Hz = 36.8 * 136 ohms
Reactance at 20.3 kHz =
\[\frac{36.8\times 136}{20.3\times 10^{3}}=you\ can\ calculate\]