For the following reaction, 5.08 grams of hydrogen sulfide are mixed with excess oxygen gas. The reaction yields 2.45 grams of water.

2 H2S (g) + 3 O2 (g) = 2 H2O (l) + 2 SO2 (g)

(1) What is the theoretical yield of water ?

grams

(2) What is the percent yield for this reaction ?

%

Question

For the following reaction, 5.08 grams of hydrogen sulfide are mixed with excess oxygen gas. The reaction yields 2.45 grams of water.


2 H2S (g) + 3 O2 (g) =  2 H2O (l) + 2 SO2 (g)





(1) What is the theoretical yield of water ? 

grams



(2) What is the percent yield for this reaction ? 

%

anonymous · Answer

I think you just substitute in the grams for the variables  but im not sure let me see if i can get someone to help us

anonymous · Answer

@Mertsj @.Sam. Can you help us?

mertsj · Answer

Change the grams of hydrogen sulfide to moles of hydrogen sulfide

mertsj · Answer

How can sulfur be 16?  Oxygen is 16?

toxicsugar22 · Answer

sulfer is 32 sorry

toxicsugar22 · Answer

so 32  for sulfer and 1 hydrogen

mertsj · Answer

So 1 mole of hydrogen sulfide is 34 grams.  Would you agree?

mertsj · Answer

|dw:1363830120875:dw|