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Given the following reactions and their equilibrium constants, C(s)+CO2(g) to 2CO K=2.4E-9 COCl2(g) to CO(g)+Cl2(g) K=8.8E-13 Calculate the K for the reaction C(s) +CO2(g)+2Cl2(g)to 2COCl2(g)
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I was trying to write out the whole thing but more easily, did you make the second equation to have coefficients of 2, so then you have to square the 8.8e^-13?
i think you say in your note to me that you did mult by 2, but you have to square the Kp value not just mult it by 2
the 8.8e^-13 is squared, but it is the inverse squared as in, 1/(8.8e^-13)^2 So, the final answer is the value from the first equation, 2.4e^-9 * 1/(7.74E-25) Do that and you get 3.1E15!! yayyy
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