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Mathematics 15 Online
OpenStudy (anonymous):

The curve above is the graph of a sinusoidal function. It goes through the point (4,0). Find a sinusoidal function that matches the given graph.

OpenStudy (anonymous):

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

this far i have -3sin... i forget how to get b.

hartnn (hartnn):

the amplitude is always positive, so +3 +3 sin (....) the phase shift is 90 degrees, so you can write, 3sin (ax+b) = 3sin (90-ax) (or = 3cos ax, because sin(90-t)=cos t )

hartnn (hartnn):

what general form you were using that included 'b' ?

OpenStudy (anonymous):

Atrigfunctionhere(BX+C)

hartnn (hartnn):

oh, so, y=Asin (bx+c) where A = +3, c =90 degrees and you wanted b, right ?

OpenStudy (anonymous):

yes.... but i am not sure how to come to the answer.

hartnn (hartnn):

plug in in the point (4,0) x=4,y=0 in y=3sin (bx+90)

OpenStudy (anonymous):

3sin b*4+90= c?

hartnn (hartnn):

0=3sin (4b+90) but i don't think that will give you answer in standard form you require.

OpenStudy (anonymous):

and the amp should be neg because from 0 to 1 it is decreasing to the minimum.

OpenStudy (anonymous):

no i am trying to find the equation to the graph... and it has to be exact because its web workk.

hartnn (hartnn):

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