Question

Help Please.... When adding polynomials what do you do? how do you the expoenets? How do you divide and multiply polynomials. Please Help explain rules thanks

Answer 1

you add like terms

so x^2 and 3x^2 are like terms which means x^2 + 3x^2 = 4x^2

but

x^2 and 3x^6 are NOT like terms, and you just leave it as x^2 + 3x^6

Answer 2

you would do this for every term

Answer 3

make sense?

Answer 4

Yes thank you what if it were in fraction form like this \frac{ 2y{ y(4y-1)} + \frac{ 5}{ 4y-1}

Answer 5

you would have to make sure the denominators were equal before you could add the fractions

Answer 6

Can you show me how please

Answer 7

what's the LCD

Answer 8

4y-1? @jim_thompson5910

Answer 9

close

Answer 10

y(4y-1) @jim_thompson5910

Answer 11

better

Answer 12

so each fraction needs to have an LCD of y(4y-1)

Answer 13

4y^2-y @jim_thompson5910

Answer 14

no need to distribute

Answer 15

you just need to make sure each denominator has y(4y-1) in it

Answer 16

How do i make it that they both have y(4y-1)

Answer 17

@jim_thompson5910

Answer 18

multiply top and bottom of the second fraction by y to get this

Answer 19

\[\Large \frac{ 2y}{ y(4y-1)} + \frac{ 5}{ 4y-1}\]


\[\Large \frac{ 2y}{ y(4y-1)} + \frac{ 5y}{ y(4y-1)}\]

Answer 20

now you can add the fractions

Answer 21

\[\frac{ 7y }{ y(4y-1) }\] is that the answer? @jim_thompson5910

Answer 22

then reduce

Answer 23

\[\frac{ 7y }{ 4y ^{2}-y }\] @jim_thompson5910

Answer 24

no

Answer 25

notice a pair of terms will cancel

Answer 26

The y? @jim_thompson5910

Answer 27

yes

Answer 28

what's the final answer

Answer 29

\[\frac{ 7 }{ 4y ^{2} }\] @jim_thompson5910

Answer 30

no

Answer 31

it would just be

\[\Large \frac{ 7}{ 4y-1 }\]

Answer 32

oh ok and can i ask more questions please? i need you to revise my answers is that okay @jim_thompson5910

Answer 33

how many questions are we talking about

Answer 34

7 @jim_thompson5910

Answer 35

If yourbusy thats ok you dont need to keep helping me youve done enough

Answer 36

I can do a few, but idk about 7

Answer 37

Ok thank you and are you sure? @jim_thompson5910

Answer 38

yeah I'm sure

Answer 39

Thank you=) \[(4a ^{4}b ^{3}+ 4a ^{3}b ^{2})+(5a ^{3}b ^{2}-4a ^{4}b ^{3})= 9a ^{3}b ^{2}\] is that right? @jim_thompson5910

Answer 40

one sec

Answer 41

that is correct

Answer 42

\[4xy(x+y)= 4x ^{2}y+4xy ^{2}\] @jim_thompson5910

Answer 43

good

Answer 44

\[(x ^{3}+y ^{3})(x ^{3}-y ^{3})= x ^{6}-y ^{6}\]

Answer 45

correct, I can do one more

Answer 46

I need help on this one \[3x ^{7}+6x ^{6}-9x ^{5}+6x ^{4}\] i need to find gcf and i need to factor the expression. is the gcf 3x^7 and how do i factor the expression?

Answer 47

@jim_thompson5910

Answer 48

the GCF is 3x^???

Answer 49

replace ??? with the correct exponent (it's not 7)

Answer 50

6? @jim_thompson5910

Answer 51

no

Answer 52

4? @jim_thompson5910

Answer 53

better

Answer 54

GCF is 3x^4

Answer 55

why is it four? @jim_thompson5910

Answer 56

because x^7, x^6, etc aren't factors of x^4

Answer 57

but x^4 is a factor of x^4, x^5, x^6, etc

Answer 58

oh ok how do i facot out the expression?

Answer 59

use the distributive property, just in reverse

Answer 60

would it be \[3x ^{4}(x ^{3}+2x ^{2}-3x+2)\] @jim_thompson5910

Answer 61

good, that's how far you can go

Answer 62

you can't factor any further

Answer 63

so thats the answer? @jim_thompson5910

Answer 64

yes

Answer 65

thank you so much for your help @jim_thompson5910