Question

Solve the equations:

Answer 1

\[4x^2-5xy+y^2=10, 3x^2-3xy-y^2=5\]

Answer 2

^system of equations

Answer 3

anyone there ?? :/

Answer 4

so, what i would do is this:
4x^2−5xy+y^2=10
-(3x^2−3xy−y^2=5
x^2-2xy=5

Answer 5

solve for y

Answer 6

then plug in the values and solve for x

Answer 7

i multiplied eqn 1 by 3 and 2 by 5 and then subtracted both i got -3x^2+8y^2=5

Answer 8

am i doing it right?

Answer 9

is there any online system of equations solver?

Answer 10

wolfram :)

Answer 11

actually, this question can solved by elimination and subtitution method

Answer 12

how plz tell me??

Answer 13

plz can someone tell me what is the type of these equations??

Answer 14

http://openstudy.com/study#/updates/50716375e4b0c2dc8340d263

Answer 15

i've asked this question before ;)

Answer 16

http://www.wolframalpha.com/input/?i=solve%28%284x%5E2-5xy%2By%5E2%3D10%29%2C%283x%5E2-3xy-y%5E2%3D5%29%2C++%28x%2Cy%29%29

Answer 17

the answer is correct !! but i should be able to see the steps

Answer 18

thanks btw

Answer 19

i found a question like this in my book

Answer 20

it is an example... which is solved!!

Answer 21

well, there is a nice way to solve it!
4x^2 - 5xy + y^2 = 10 ... (1)
3x^2 - 3xy - y^2 = 5 ... (2)

division from (1) and (2), giving us :
(4x^2 - 5xy + y^2)/(3x^2 - 3xy - y^2) = 10/5
(4x^2 - 5xy + y^2)/(3x^2 - 3xy - y^2) = 2
cross product :
4x^2 - 5xy + y^2 = 6x^2 - 6xy - 2y^2
simplify !
2x^2 - xy - 3y^2 = 0
factor out !
(2x - 3y)(x + y) = 0
the solution of this, are
x = 3y/2 or
x = -y

Answer 22

now, subtitute of both (x's) to one of equations above!
example, i take the 1st equation :
4x^2−5xy+y^2=10
try for the first x, is x=3y/2
4(3y/2)^2−5(3y/2)y+y^2=10
4(9/4)y^2 - 15y/2 + y^2 = 10
simplify !
y^2 = 4
y = +- 2

subtitute back to x = 3y/2
so, x1 = 3(2)/2 = 3 ----> solution (3,2)
x2 = 3(-2)/2 = -3 -----> solution (-3,-2)

Answer 23

now, for u the rest :)

Answer 24

take x = -y
and subtitute to 4x^2−5xy+y^2=10, so that all terms in y
solve for y, then subtitute back to x=-y to get the value of x
u'll get order pairs as solutions