calcII show that for any integer n>=0, we have int{0,1}(lnx)^ndx=(-1)^n(n!)
its straight forward... I almost finished it and accidentally the page got refreshed! :( too late (gotta sleep) use the substitution \(\ln x=-u\implies x=e^{-u}\) you'd keep getting integration by parts that will keep giving you \(n(n-1)(n-2)\ldots\) the \((-1)^n\) shows up right after the substitution.
that's why you keep on hitting post every few lines. atleast that's what i do.
my biological CPU is shutting down..
but thanks, i'll try to solve it from here.
ya, you should go to bed.
hey experiment do you think you help explain the rest of this to me?
where do you need help?
i don't really understand what electro did there.
this is pretty staring forward.|dw:1363843551584:dw|
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