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Mathematics 15 Online
OpenStudy (anonymous):

calcII show that for any integer n>=0, we have int{0,1}(lnx)^ndx=(-1)^n(n!)

OpenStudy (anonymous):

its straight forward... I almost finished it and accidentally the page got refreshed! :( too late (gotta sleep) use the substitution \(\ln x=-u\implies x=e^{-u}\) you'd keep getting integration by parts that will keep giving you \(n(n-1)(n-2)\ldots\) the \((-1)^n\) shows up right after the substitution.

OpenStudy (anonymous):

that's why you keep on hitting post every few lines. atleast that's what i do.

OpenStudy (anonymous):

my biological CPU is shutting down..

OpenStudy (anonymous):

but thanks, i'll try to solve it from here.

OpenStudy (anonymous):

ya, you should go to bed.

OpenStudy (anonymous):

hey experiment do you think you help explain the rest of this to me?

OpenStudy (experimentx):

where do you need help?

OpenStudy (anonymous):

i don't really understand what electro did there.

OpenStudy (experimentx):

this is pretty staring forward.|dw:1363843551584:dw|

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