Question

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together.
y=3-x^2, (-1,2)

Answer 1

the form of the equation tangent to given curve f(x) is:
\[y-y_0=f'(x_0)(x-x_0)\]
inyour case: \((x_o,y_0)=(-1,2)\), \(f'(x)=-2x\) and \(f'(x_0)=f'(-1)=2\)