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Mathematics 15 Online
OpenStudy (anonymous):

please help differentiation tan x

OpenStudy (anonymous):

http://lmgtfy.com/?q=derivative+of+tanx

OpenStudy (anikhalder):

\[\sec ^{2}x\]

OpenStudy (anonymous):

please help yo diffrention up to five times

OpenStudy (anonymous):

derivative of sec x is sec x tan x have fun with the product rule... or you could use the quotient rule if you feel like banging your head into a wall.

OpenStudy (anonymous):

tanx=(sin x divided by cos x) rite... so when u differentiate (sin x over cos x) you get \[\left((\cos ^{2}x + \sin^{2}x)\div \cos^{2}x) \right) \] and as \[(\cos ^{2}x + \sin^{2}x)=1\] it equals \[\left((1)\div \cos^{2}x) \right) \] which equals \[\sec ^{2}x\]

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