Question

I do not understand why..
1/z(z-1)^2 = 1/z (1-z)^-2

Answer 1

\[\frac{ 1 }{z(z-1)^2 } = \frac{ 1 }{z }(1-z)^-2\]

Answer 2

are you sure you not missing a minus sign?

Answer 3

nope double and triple checked.

Answer 4

that's squared ...

Answer 5

what is squared?

Answer 6

Maybe you need something along the lines of...
\[\Large a^2=(-a)^2\]:D

Answer 7

oh i get what is squared.. the -1 is taken out of the brackets but it has to be squared so becomes 1..
they have done that so it is in the form of the basic Taylor series..

Answer 8

yes terenz...

Answer 9

Then that's settled? Unless I'm missing something, and I highly suspect that to be the case :D

Answer 10

no I think i get it. I was simply over thinking or under thinking..
but now it all makes sense in context to what I am being asked.
Thanks