Question

A(cross)B=2i + j - k [cross means cross product]
A + B=i -j + k
The least value of |A| is?

where A and B are vectors.

Answer 1

@shubhamsrg @DLS

Answer 2

@shubhamsrg aa gya tu :')

Answer 3

abhi kaha :/

Answer 4

solve kr isko.

Answer 5

kya? kr na....

Answer 6

rukna :P

Answer 7

acha solve krte raheyo mai chala. :P

Answer 8

mai solve nahi kar raha abhi :P
rukna :P

Answer 9

Dude solve kr. Ya bta de kaise krna hai. :/

Answer 10

hmm,
am back.. :P

Answer 11

arre shubham pehle wo answer dekh :P

Answer 12

post bhi kr ab....

Answer 13

sochne do..
|a||b| sin@ = sqrt6
|b| = sqrt6/|a|sin@

aur, |a|^2 + |b|^2 + 2|a||b| cos@ = 3

=> |a|^2 + 6/|a|^2 sin^2@ + 2sqrt6 cot@ =3

|a|^2 = x maan raha hu simplicity ke liye

simplify karenge, to ayega :

sin^2 @ x^4 - (3 - 2sqrt6 cot@)x^2 + 6 = 0

x^2 = [ (3 - 2sqrt6 cot@) +/- sqrt( 9 + 24cot^2 @ - 12sqrt6 cot@ - 24 sin^2 @) ]/2sin^2 @

x min hoga to x^2 bhi min hoga
ques ho gaya minimize RHS

wtf! :P

Answer 14

koi calc mistake ki kya kahi ?

Answer 15

I can only give you the options. :P
a) 1/sqrt2
b) 2
c) sqrt2
d) (sqrt2)-1

Answer 16

@RnR A)

Answer 17

acha agar aise karein :

a+ b = i-j + k
axa + bxa = (i-j+k)xa

-2i -j + k = sqrt3 * |a| * sin@ * n^

=> sqrt2 = |a| sin@

least value = sqrt2

c)
B|

Answer 18

c) hai na? @RnR

Answer 19

:P

Answer 20

-2i -j + k = sqrt3 * |a| * sin@ * n^ ye kya kiya hai?
pta nhi ans nhi hai...

Answer 21

ye torque kitna hoga?
@RnR @shubhamsrg :P