Which shows ^6 sqr rt (24)^2 in simplified radical form with the smallest possible index?

Question

Which shows ^6 sqr rt (24)^2  in simplified radical form with the smallest possible index?

tanner23456 · Answer

Is this what you mean?
$$\sqrt[6]{24^2}$$

If that's the case put it in exponential form first.

24^(2/6)

reduce the fraction in the exponent to simplest form and put it back in radical form

anonymous · Answer

yesh!! thanks the multiple choices r.. $$2 ^3\sqrt{3}$$ $$3 \sqrt[3]{4}$$ $$4 \sqrt[3]{3}$$  $$6 \sqrt[3]{4}$$

tanner23456 · Answer

ok so when you reduce the fraction you get

$$24^{1/3} or \sqrt[3]{24}$$

now factor out the 24 to 2*2*2*3

notice their are 3 2's so we can pull out a 2

so you're left with

$$2\sqrt[3]{3}$$

anonymous · Answer

thank yoooooouuu :D *bug hug*

anonymous · Answer

the fuq? who r u?

tanner23456 · Answer

Don't worry about it. @tywan has been doing this to several people.

anonymous · Answer

okay i was like gasp!! ive never done tht stuff