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\[f(x) = \ln(x-1), [2,4].\](Application of the Mean Value Theorem), find the value of c that satisfies it.)\[f'(x) = \frac{ 1 }{ x-1 }\]\[f(b)=\ln(4-1) = \ln(3)\]\[f(a)=\ln(2-1)=\ln(1)=0\] \[f'(x) = \frac{ f(b) - f(a) }{ b-a }\]\[\frac{ 1 }{ x-1 }=\frac{ \ln(3)-(0) }{ 4-2 }=\frac{ \ln(3) }{ 2 }\]\[\frac{ 2 }{ x-1 }=\ln(3)\]\[x-1 = \frac{ 2 }{ \ln(3) }\]\[x = \frac{ 2 }{ \ln(3) }+1\]Does this look right to everyone?
looks good.
Kay, thanks.
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