assume that 21 year old womens heart rates at rest are normally distributed with a mean of 74 beats per minute and a standard deviation of 2 beats per minute. if 200 women are examined, how many would you expect to have a heart rate of less than 75?
hopefully you remember the calculator we used last time if not, here it is http://www.wolframalpha.com/input/?i=normalcdf&a=*C.normalcdf-_*Formula.dflt-&f2=75&x=6&y=4&f=NormalProbabilities.z_75&f3=74&f=NormalProbabilities.mu_74&f4=2&f=NormalProbabilities.sigma_2&a=*FVarOpt.1-_***NormalProbabilities.z--.***NormalProbabilities.pr--.**NormalProbabilities.l-.*NormalProbabilities.r---.**NormalProbabilities.mu-.*NormalProbabilities.sigma---
the value you want is on line 1, which is 0.6915 (since it's the value for P(Z < 75))
your last step is to multiply that with 200 to get your final answer
138.3?
got the same
so you round that to the nearest integer (because we're talking about a number of people) to get 138
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