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Physics 18 Online
OpenStudy (anonymous):

Please help with this question. Thansk :)

OpenStudy (anonymous):

http://screencast.com/t/ywl5dueJVG8Y

OpenStudy (anonymous):

@Yahoo! @Preetha

OpenStudy (anonymous):

@.Sam.

OpenStudy (unklerhaukus):

well for a start, the pressure of the gas enclosed must be greater than atmospheric pressure right?

OpenStudy (anonymous):

yes, or else the water wouldnt be pushed further right

OpenStudy (anonymous):

@Callisto

OpenStudy (anonymous):

The pressure in a fluid at rest is the same for all points at the same level. p=p_0 + ugh u: density h: height g: gravity p_0: atmospheric pressure (in this case). p: pressure I found (C) 1.5x10^5 Pa.

OpenStudy (anonymous):

pressure of the gas = pressure of the liquid + atmospheric pressure

OpenStudy (anonymous):

how did u calculate pressure of the liquid

OpenStudy (anonymous):

p=p_0 + ugh = (1.0x10^5 Pa) + (1000 kg/m^3)(10 m/s^2)(5.0 m). The height is 5.0m because the pressure in a fluid at rest is the same for all points at the same level, the dotted line implies that the point where the gas encounters the water is the same as 5.0 m from te end of the tube.

OpenStudy (anonymous):

thanks alot bro :)

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