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Mathematics 16 Online
OpenStudy (anonymous):

factor plzzz 8x^3 + 4x^2 - 2x - 1

OpenStudy (tkhunny):

Have you tried grouping? It can be a useful last resort prior to punting. Take the first two separately 8x^3 + 4x^2 4x^2 (2x + 1) Take the second two separately. - 2x - 1 -(2x+1) Putting it back together 4x^2 (2x + 1) - (2x+1) Do you now see how to proceed?

OpenStudy (anonymous):

no?

OpenStudy (tkhunny):

Now, you have two terms. Both terms have (2x+1) as a factor. Now do you see it?

OpenStudy (anonymous):

ya but what do i do?

OpenStudy (tkhunny):

Factor it, just like any other factoring. (4x^2 - 1)(2x + 1) Stare at that for a little while until you see it. After that, decide if there is more to factor or if we are done factoring.

OpenStudy (tkhunny):

Did you decide if this is done?

OpenStudy (anonymous):

more right?

OpenStudy (tkhunny):

Yes. What part?

OpenStudy (anonymous):

2x

OpenStudy (tkhunny):

"2x" isn't a part to be considered. You must consider ONLY the FACTORS of the expression. Can you identify the factors? There are two of them.

OpenStudy (tkhunny):

Well, it's past my bedtime. (2x+1) -- No more factoring. (4x^2 - 1) -- More factoring. You should recognize the difference of squares. Good luck.

OpenStudy (anonymous):

breaks down into (2x+1)(2x-1)

OpenStudy (anonymous):

and the last one you had (2x+1)

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