Question

Calculate the dissociation energy of NaBr(g). Express your answer in kJ/mol.

Data
NaBr Madalung constant 1.75
NaBr Born exponent 8
Na+ Radius 116e-12 m
Br+ Radius 182e-12 m
K+ Radius 152e-12 m

Answer 1

408 KJ/mole

Answer 2

how did you get that???

Answer 3

E = e^2x(4xπxε0xr0)^-1x(1-n^-1);
e- = 1.602*10^-19 eV;
ε0 = 8.854*10^-12;
r0 = (116+182) = 298*10^-12 m;

E = 6.77*10-19 J or 408 KJ/mol.

Answer 4

cool guys

Answer 5

where did u guys keep madalungs constant

Answer 6

madalungs constant for crystals or solid this is a gas

Answer 7

oh i see

Answer 8

thanks

Answer 9

what if you are calculating the cohesive energy

Answer 10

E= -M*NA*e2*1/(4*π*ε0*r0)*(1-1/n);
e-= 1.602*10^-19;
ε0= 8.854*10^-12;
r0= (116+182): 298*10^-12;
M= 1.75;
n= 8.

E = - M*e^2x(1/4xπxε0xr0)x(1-1/n).

Answer 11

i did all that

i seem not to pay attention to my calculations very much

i had the wrong answer but i am fine with it

Thanks anyway