Question

what would be the poles for the follwoing funciton?

1/(2z^2 +7iz − 3)^2

would it be

pole at z=-i/2 of order 2 and pole at z=-3i of order 2??

Answer 1

solve (2z^2 +7iz − 3) = 0

Answer 2

both roots would be poles of it ... since it has ^2 ... should of order 2

Answer 3

but all that is also squared too...

anyhow I get (2z+i)^2(z+3i)^2=0

so z=-i/2 of order 2 and z=-3i of order 2

Answer 4

yes ...

Answer 5

thanks

Answer 6

you should always follow from definition.