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Mathematics 8 Online
OpenStudy (anonymous):

Help?

OpenStudy (anonymous):

OpenStudy (anonymous):

I think it's 90.

Directrix (directrix):

I don't know the answer yet. The theorem at work here is this: If a line is parallel to one side of a triangle and intersects the other two, then it divides them proportionally. That theorem will be used twice to get the two sides.

OpenStudy (anonymous):

Yeah, it's 108

OpenStudy (anonymous):

Thank you! :)

Directrix (directrix):

Look on the attachment for an equation to solve.

Directrix (directrix):

@Annetta_Martin Are you saying that you have solved this problem?

OpenStudy (anonymous):

Yes, I didn't know before that "If a line is parallel to one side of a triangle and intersects the other two, then it divides them proportionally." So I took that into consideration, solved it and I got 108 :)

Directrix (directrix):

As it turned out, I used corresponding sides of similar triangles are in proportion. What did you get for CF?

Directrix (directrix):

CF = DE because opposite sides of a parallelogram are congruent.

OpenStudy (anonymous):

EF = 72 DE = 36

Directrix (directrix):

EF/AC = BC /BA EF/90 = 120/150 EF = ?

OpenStudy (anonymous):

I'll show you how I did it....

Directrix (directrix):

Okay.

OpenStudy (anonymous):

BA = AC BE = EF. EF = BE*AC/BA EF = 72. BC = CA BF = FE BF = FE*BC/CA BF = 144

Directrix (directrix):

I got 72 for EF.

OpenStudy (anonymous):

That's correct.

OpenStudy (anonymous):

And DE is equal to CF

Directrix (directrix):

DE + DF = 36 + 72 = 108. You had 90.

OpenStudy (anonymous):

At first I thought it was 90 for some reason, but after doing the math I also got 108 as my answer.

Directrix (directrix):

That sounds good. :) So, I guess we are finished with this problem.

OpenStudy (anonymous):

Yes we are, thank you for everything @Directrix! :D

Directrix (directrix):

Alrighty, then. I'm happy to help. :)

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