Help?
I think it's 90.
I don't know the answer yet. The theorem at work here is this: If a line is parallel to one side of a triangle and intersects the other two, then it divides them proportionally. That theorem will be used twice to get the two sides.
Yeah, it's 108
Thank you! :)
Look on the attachment for an equation to solve.
@Annetta_Martin Are you saying that you have solved this problem?
Yes, I didn't know before that "If a line is parallel to one side of a triangle and intersects the other two, then it divides them proportionally." So I took that into consideration, solved it and I got 108 :)
As it turned out, I used corresponding sides of similar triangles are in proportion. What did you get for CF?
CF = DE because opposite sides of a parallelogram are congruent.
EF = 72 DE = 36
EF/AC = BC /BA EF/90 = 120/150 EF = ?
I'll show you how I did it....
Okay.
BA = AC BE = EF. EF = BE*AC/BA EF = 72. BC = CA BF = FE BF = FE*BC/CA BF = 144
I got 72 for EF.
That's correct.
And DE is equal to CF
DE + DF = 36 + 72 = 108. You had 90.
At first I thought it was 90 for some reason, but after doing the math I also got 108 as my answer.
That sounds good. :) So, I guess we are finished with this problem.
Yes we are, thank you for everything @Directrix! :D
Alrighty, then. I'm happy to help. :)
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