Question

...

Answer 1

isnt the answer just (x-7)(x-7)=0 so its 7?

Answer 2

ooo jk then

Answer 3

find the value of ?

then you'll have to get the equation into the form

\[(x -h)^2 = 4a(y - k)\]

Answer 4

I don't understand, its confusing

Answer 5

this process will use the vertex form... of the parabola equation.

Answer 6

Ok...hold on

Answer 7

x + -3)(x + -3) = -27

Answer 8

Thats what i got

Answer 9

sorry i took long

Answer 10

ok... I need to start again... I made an error

\[x^2 - 6x + 9 - 8y + 40 = 0\]

this becomes

\[(x - 3)^2 = 8y - 40\]

factor out the 8 on the right

\[(x -3)^2 = 8(y - 5)\]

does this make sense...?

Answer 11

How do you factor out 8 on the right, thats the probelm

Answer 12

well 8 * y = 8y and 8*5 = 40

I split 49 into 2 parts

the 9 needed to complete the square in x..

that left 40....

Answer 13

I mean, I want to know how that person got 1/8

Answer 14

well in the vertex from they had

\[8y = (x -3)^2 + 40...divide..by ..8.....y = \frac{1}{8}(x -3)^2 + 5\]

Answer 15

I was thinking the reason was 1/4c

Answer 16

so using the vertex form its

\[y = \frac{1}{8}(x -3)^2 +5\]

does that now make sense..?

Answer 17

correct...

for the focus you need to find the focal length...

I write the equation in the form

\[(x -h)^2 = 4a(y - k)\]

(h, k) is the vertex and a is the focal length...

so going back a couple of steps...

I would have the equation as

\[(x -3)^2 = 4 \times 2(y - 5)\]

so the focal length is a = 2

then the focus is found by adding the focal length to the vertex value for y.

(3, 5+2)

Answer 18

My method is probably slightly different to the method you may use... as its just the way its taught in Australia.

Answer 19

Oh never mind i get it

Answer 20

thank you

Answer 21

I'll give you a medal