Question

Please help me solve the following problem. To complete your master's degree in physics, your advisor has you design a small, linear accelerator capable of emitting protons, each with a kinetic energy of 8.9 keV. (The mass of a single proton is 1.67 10E-27 kg.) In addition, 1.00 10E9 protons per second must reach the target at the end of the 1.80-m-long accelerator.
(a) What the average power must be delivered to the stream of protons?

Answer 1

I'm in a mechanics class so these units are a bit foreign to me.

Answer 2

Given that:
\[E = 8.9\times10^3\rm{eV}\qquad\text{(per proton)}\\
m_p=1.67\times10^{-27}\rm{kg}\\
n_p=\quad\text{number of protons. I do not understand the number you put up there}\\
L=1.8\rm{m}
\]
total power per sec = \(n_p\times W_p\)
\(W_p=\) work done to accelerate each proton

Answer 3

eV = electron Volt = units for energy = \(1.6\times10^{-19}\)J

Answer 4

sorry i forgot to put E before the exponent

Answer 5

Still not sure what to do, any help greatly appreciated.

Answer 6

how much work is done to accelerate the protons?

Answer 7

W = final energy - initial energy

Answer 8

final energy = given
initial energy is due to ____?

Answer 9

W=1.60E-19J

Answer 10

I guess it is safe to assume the initial energy is zero.

Answer 11

there is too much of uncertainty in my answer.

but we can find the potential required by the formula
E=eV = charge x electric potential

we get, V= 8.9E3 v
for n=1E9 particles

V= 8.9E12 v

and now i'm not sure about the relation of potential and power. sorry. but tell me if you get to know that

Answer 12

\[P=\frac{\Delta E}{\Delta t}\]
In his information, it is 1E9 particles per second.